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Originally Posted by Uncle`BuZZ
The answer is evident on this graph, not on your where we don't know nothing about input.
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Don't know input? Huh?
The graph shows exactly what the input is to sustain the 5C air-water temperature delta at equilibrium.
All the information that is on the graph that I presented from BillA's excellent article is enough to formulate a C/W graph for the radiator's performance with respect to flow rate - simply divide 5C by the input power (watts) shown to arrive at the C/W for that flow rate.
Multiple the resulting C/W axis by the CPU watts (71W) and you would arrive at the exact same graph as lolito_fr presented above.
I don't believe you are stupid. I am glad that you are thinking about it deep enough to get yourself perhaps a little confused, but that's a good thing. A least you're thinking!