Following the Artic Silver article above for reference;
1667mhz @ 1.75V
CPU: 42.43C Water In: 26.94C DT: 15.49C
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667mhz @1.75V
U: 33.50 Water In: 25.52C DT: 7.97C
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1667/667 = 2.5
15.49/7.97 = 1.94
Shave 3C off;
CPU 39.42C Water In: 26.94C DT: 12.49C
CPU 30.50C Water In : 25.52C DT: 4.98C
12.49/4.98 = 2.5
So can I conclude I need to subtract 3C from my CPU measurments?
Last edited by jaydee116; 04-08-2005 at 05:01 PM.
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