Post your ridiculous wc marketing here!

[satanicoo]

Originally posted by airspirit
...Did you notice how in that Tom's review he mentioned that head doesn't matter in a closed loop (dumbass), says if distilled water with additives leaks on your system it won't short out (stupid stupid stupid)...

but in a closed loop head doesnt matter right? we only use high head pumps because of the flow restriction, if i have understand correcty

distilled whater shouldn't short the system, its 5v and 12 v arent enouf for passing energy. but i dunno about distilled water with addictives.

plz correct me if wrong.

all the rest correct, including tom=dumb

on topic:
http://www.biomag.org/product_105.html

i specially loved this part

"In a conventional air cooling unit (Figure 2), the CPU is in direct contact with the heat sink. If fan speed is reduced, the heat sink will become hotter. The CPU, which is in contact with the heat sink, will also become hotter. "

The heatsink heats the Processors? we are such a sukers, lets just remove them

[airspirit]

Head indicates how much resistance the pump can overcome at a given flow rate. If you had a pump that could pump 30000 GPM but had a maximum head of one inch, it probably wouldn't be pumping much through your system ... if it pumps at all.

[8-Ball]

Originally posted by Tweety
And in addition states that by transferring heat more efficiently to the water you use your radiator more efficiently because the difference between watertemps and room temps are higher...

Not true, If the temperature differential between the water and the ambient air were increased, then more thermal energy would be transferred from the rad than is being transferred into the water from the block.

If thermal energy is transferred more efficiently into the water, then the processor cools down, because a lower temperature differential is required between cpu and water.

8-ball

[airspirit]

That is a really murky statement. If you can assume that heat is being pulled more efficiently into the water via the block (like a WW when compared to a Senfu), then naturally the water will be a little warmer, and this would cause the radiator to transfer more heat. How they stated it, though, is really stupid, and is a case of making alot of noise about nothing ... and stating it backwards perhaps to deliberately confuse the customer and hopefully gaining a sale because of the long-winded description that means that it has to be good ... right? They should have summed it up as "a more efficient water block."

[BillA]

Originally posted by airspirit
That is a really murky statement. If you can assume that heat is being pulled more efficiently into the water via the block (like a WW when compared to a Senfu), then naturally the water will be a little warmer, and this would cause the radiator to transfer more heat. How they stated it, though, is really stupid, and is a case of making alot of noise about nothing ... and stating it backwards perhaps to deliberately confuse the customer and hopefully gaining a sale because of the long-winded description that means that it has to be good ... right? They should have summed it up as "a more efficient water block."

tilt

[8-Ball]

Originally posted by airspirit
That is a really murky statement. If you can assume that heat is being pulled more efficiently into the water via the block (like a WW when compared to a Senfu), then naturally the water will be a little warmer, and this would cause the radiator to transfer more heat. How they stated it, though, is really stupid, and is a case of making alot of noise about nothing ... and stating it backwards perhaps to deliberately confuse the customer and hopefully gaining a sale because of the long-winded description that means that it has to be good ... right? They should have summed it up as "a more efficient water block."

No, if the heat is, as you put it, pulled more efficiently from the processor, then a lower temperature differential will be required between the cpu and the water (the average water temp for a given heat load being determined by the radiator, the ambient air temp and the airflow, NOT the waterblock), thus the cpu can be cooler while still dissipating the same heatload into the water.

The efficiency of the waterblock determines how much hotter the cpu must be than the water, NOT the other way round.

8-ball

[airspirit]

Man, mebbe I'm just confused (still hung over from last night ... dizzy and hurting).

DAMN YOU MARKETING BASTARDS FOR FSCKING WITH MY HEAD!

In the end, the coolant temperature will be slightly higher if the block is more efficient. Basically, if you have X amount of heat generated from the CPU, it all has to go somewhere. If the block is less efficient, that heat will be partially absorbed by other components than the water such as the block itself (i.e., having a hot block but cool coolant), the CPU packaging (god forbid) and the motherboard, etc. The heat has to go somewhere ... the chip doesn't get rid of it by staying hotter. If the chip temp goes down due to a more efficient block, the water temperature will go up ever so slightly.

The difference won't be that noticable, but the difference will be there. It HAS to be. Heat doesn't just disappear.

That make more sense?

Damn ... I need some meds. I think I have a migrane coming on. I'm starting to get the tunnel vision thing and these weird faded spots in my vision ... and damn does my stomach hurt. This has to be more than a damn hangover.

[airspirit]

I guess the best way to explain that would be to take a heat source, like a soldering iron, and place it in a bucket of water. The bucket will cool via evaporation, simulating the radiator in this case. When you plug in the iron (increasing the heat load to simulate the increased block efficiency), the water will heat up, and the water will evaporate faster (simulating the greater efficiency of the radiator under greater dTs). Regardless of the fact that the water is evaporating faster, though, the water will be warmer than before. Now, the difference we are talking about isn't as large as turning a soldering iron on, but it is there. There will be an increase in coolant temperature if a waterblock is more efficient.

[BillA]

lol, stay with the slime

no, eh
read what 8 ball is saying
do NOT try to think up analogies

a given applied heat (load), will heat the coolant 'x' amount;expressed in Watts, and dependant on the flow rate will result in a FIXED temp rise
(really basic physics here, google 'heat capacity calculations')

the efficiency of a wb will be apparant in the temp gradient across it
i.e. how hot does it have to get to transfer that 'fixed' amount of heat into the coolant

back to the slime pit, boy

[Zhentar]

Airspirit- I can say I've felt how you do, this physics stuff can be so confusing. The thing to remember is no matter what the processor dissipates X watts of heat at equilibrium. It does seem like to bring the CPU temperature lower, we have to dissipate more heat, right? but thats wrong, if you "dissipate more heat" with some change, your processor is not at equilibrium anymore, and the temperature will fluctuate to a new temperature where it will dissipate X watts of heat again. The difference between all heatsinks and waterblocks, is the delta T required to dissipate X watts. Poor cooling needs a very high delta T between the Die and the coolant(air or water) to be able to dissipate X watts, while better cooling needs a lower delta T.

[Les]

Originally posted by unregistered

....
a given applied heat (load), will heat the coolant 'x' amount;expressed in Watts, and dependant on the flow rate will result in a FIXED temp rise
..........

The heat load is dependant on the heat losses through paths other than the wb. The size of these secondary heat losses is dependant on the efficiency of the wb. For example:-

[hara]

In other words I get it that all WBs absorb pretty much the same.

[#Rotor]

Originally posted by Les
The heat load is dependant on the heat losses through paths other than the wb. The size of these secondary heat losses is dependant on the efficiency of the wb. For example:-

at a fixed temperature........ right??

[Les]

Originally posted by #Rotor
at a fixed temperature........ right??

Yes.
A fixed thermal enviroment except for the wb.

[airspirit]

So, in other words, the more efficient the block is, the more thermal energy that will be dumped into the water, correct? And this would heat up the water, correct? Am I missing something?

[BillA]

"applied heat (load)"
not so well stated, intent was to consider that specific portion of the applied heat seen as a load by the wb
obviously the secondary path 'losses' are irrelevant to an assessment of the wb's performance
(they are consequential)

and for this reason the quantification of "W" must include an assessment of the secondary losses
this can be done with a heat die - and I do so - but is about impossible using a CPU

better ?

no hara, not if they have different "C/W"s
that's what's being measured, eh ?

[BillA]

airsprit
no, again no

the whole cooling 'chain' is a cascade of gradients
more efficient = lower gradient
always same amount of heat being shuffled
(less 'losses' here and there, per Les' correction)

[satanicoo]

billa, i have this question bugging me for a long time:

imagine a cpu always dissipate 80w.

then why the diference between the idle and load?

[pHaestus]

CPUs don't produce a constant amount of heat; they use more power (and therefore generate more heat) when working than when idle.

[satanicoo]

aaaahhhh k thanks, because i have hearded that in this forums and got confused.

[Les]

Originally posted by unregistered
"applied heat (load)"
not so well stated, intent was to consider that specific portion of the applied heat seen as a load by the wb
obviously the secondary path 'losses' are irrelevant to an assessment of the wb's performance
(they are consequential)

and for this reason the quantification of "W" must include an assessment of the secondary losses
this can be done with a heat die - and I do so - but is about impossible using a CPU

better ?
.........

Fine.
Was not questioning the assessment of secondary losses.in your test results.
Sums for the Heat Die suggest any variation in load would be less than 1% in any wb's efficiency versus flow characterisation.

Dunno whether this correlation exists or is detectable.

Possibly of interest is that the R(insulation) of 15.375c/w corresponding to the experimental 98.4% absorbtion(1.6% loss) would be that calculated(Kryotherm) for a 50x50x90mm lump surrounded by 22.4mm thick layer of Polyurethane foam. Not sure but think this is not too remote from reality.

[Tweety]

8-ball... after reading your first post and disregarding all the fancy smanchy graphs and technical bibbel babbel (sorry #Rotor, BillA...) the point you made became quite clear...
My brain works better on simple explanations...

I should have caugth this one myself as I was quoting but I was kinda caugth up in the process of translating... I positively hate german... ie the language and the spelling...
Nothing against germans at all... They have 2-3 rules and 999 exceptions....

[MadDogMe]

Basicly: It may be absorbing more heat(per 'unit'), but the water's cooler in the first place because of the increased 'cooling performance'?. Therefore it's cooler?...

But if you were putting sustained 20degC water through the two blocks(no rad, just 'once used' water), it would be warmer then?...


Is any of that right?...

[8-Ball]

Not quite sure what you're referring to. If it's why the cpu is at the temperature it is, then I'll try and explain in a little more detail.

A few points.

1. Heat flows DOWN a temperature gradient.
2. The amount of thermal energy that will flow down a unit thermal gradient (ie 1 degree cooler per metre) for a block of unit cross section (1mx1m) is the coefficient of thermal conductivity.

So, for a given heat exchange process, if we want to transfer MORE thermal energy, then we need to INCREASE the thermal gradient.

If we have a fixed coolant temp and a fixed heat load, the thermal gradient must be increased until the thermal energy which will flow down the gradient matches the heat dissipation of the source. The heat source will then stay at a constant temperature, as the thermal energy it is producing is ALL being removed. This doesn't mean it will cool down, as this would reduce the thermal gradient.

The whole heat exchange from cpu to air can be considered as a series of individual heat exchanges, each with an associated thermal resistance (reciprocal of the efficiency), where a greater resistance requires a greater thermal gradient (driving force) in order to transfer the same amount of thermal energy.

1. CPU > Waterblock base - (TIM C/W)
2. Waterblock base > waterblock fins - (block C/W)
3. Waterblock fins > water - (convective heat transfer coefficient)
4. Water > radiator wall - (convective heat transfer coefficient)
5. Radiator wall > radiator fins - (radiator C/W)
6. Radiator fins > air (convective heat transfer coefficient)

For a given heat load, each of these steps will have an associated temperature difference required to transfer that exact amount of heat. These can simply be added up to find the total temperature difference between the air and the cpu, where the air temp is the controlling variable.

Factors such as flow rate, fluid viscosity, thermal diffusivity of fluid and the geometry of heat exchanger surfaces will affect the resistances/efficiencies, thus affecting the temperature difference associated with each step.

As for the difference between idle and load.

If the thermal energy load is resuced, ie, cpu at idle, then the temperature difference required at each stage to transfer that amount of thermal energy will be reduced. Thus the overall temperature difference will be reduced, and since the ambient is still at the same temperature, the cpu will cool down.

Obviously, there will be a delay due to the time it takes for the water and the copper to drop in temperature, which will happen because the heat transferred into them from the cpu will drop, yet they are still at a temperature to transfer the initial load to the next medium, so more thermal energy will be transferred out than that which is coming in, so it will cool down.

That's why larger copper blocks and systems with large volumes of water will not react so quickly to heat loads.

I hope all of that makes sense.

8-ball

[UnloadeD]

What was the topic again? Oh yea.
http://becooling.safeshopper.com/36/192.htm?780
" This is one of the highest (if not best) performing blocks currently on the market for AMD and P4 cpus. High flow, multiple, parallel 1/16" deep and wide micro channels. Channels are curved on the base to maximize turbulence. 1/2" Chrome barbs, 1/4NPT threads, black anodized aluminum cover prevents corrosion. Copper alloy 110 base is machined, lapped and polished.

O-ring design provides an excellent seal against leaks. Pretested prior to shipping."

This one seems a bit BS-ish to me.

peace.
unloaded