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General Liquid/Water Cooling Discussion For discussion about Full Cooling System kits, or general cooling topics. Keep specific cooling items like pumps, radiators, etc... in their specific forums. |
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02-10-2003, 07:31 PM | #76 | ||
Cooling Savant
Join Date: Dec 2002
Location: Florida
Posts: 256
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Quote:
Do I think impingement can out do a micro-channel block with just 3PSI? No I don't. I believe it would be an even call. 50 PSI? Sure but it isn't practical. Quote:
Last edited by SysCrusher; 02-10-2003 at 07:40 PM. |
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02-10-2003, 11:20 PM | #77 |
Pro/Guru - Uber Mod
Join Date: Sep 2002
Location: Indiana
Posts: 834
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More on power dissipation.
Continuing where I left off...
Having an equation to approximate an Eheim 1048 PQ curve makes it easy to generate some more graphs in Excel. The following graph shows aspects of a simulated watercooling system composed of a DTEK TC-4, a Big Momma Heatercore, and an Eheim 1048. (Tubing, fittings, etc. neglected blah, blah, blah) Drawing a line down from the intersection of the yellow line and dark blue line, (intersection of loop PQ and pump PQ) it can be seen that the flowrate through this system will be about 5lpm, and the power transferred from the pump to the loop will be about 0.92 Watts. (Out of about 0.94 Watts maximum pump output.) Because the system pressure drop is split about 50/50 between the TC-4 and the Big Momma, the power dissipation in the block itself will be about 0.46 Watts. From my first chart it can be seen that at 0.46 Watts dissipation the thermal resistance of the TC-4 will be about 0.226 C/W. The following chart is the same, except with a MCW462-UH simulated in place of the the TC-4. In this case it can be seen that the flowrate is a bit higher. (6.4 lpm instead of 5 lpm) The power dissipated in the loop is about the same. (0.93 Watts instead of 0.92 Watts) The power dissipated in the block is a much smaller fraction of the total power delivered by the pump. (About 5.5% or 0.05 Watts) Looking at my first graph, the thermal resistance of the MCW462-UH in this system would be about 0.246 C/W. So is there any particular value to doing watercooling system performance calculations in terms of power consumption? None that I can think of. The data Bill provides yields all these results without any need to calculate a power consumption. It's been interesting to me to look at this stuff from this perspective though. I've got a lot better feel for how the parts of the system interact. Hmm... Starting to think that Dodge Viper's putting those extra barbs on the wrong end of the heatercore. |
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