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Originally Posted by Butcher
The stated power draw of the TEC is 300W (straight off the manufacturers specs - 25A@12V = 300W). Add 100W of load to this... 300+100 = 400W, not 315W. It's not exactly a hard calculation. I'm more inclined to trust this very simple and proven formula (ohm's law is pretty much known to work) than a random spreadsheet.
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If you took those spec from swiftech page, then I will question the accuracy of their statement toward amperage vs voltage.
At the "Major features" enumeration, they write:
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226Watts 25A at 12V thermoelectric module
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But if you look further down the page, you see a table with the TEC spec, wich are
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Thermolectric module characteristics
Couples U max I max DT max Q max L ×W×H(mm) R(ohm)
127 15.2 VDC 24 A >67 ° C 226.1 W 50 × 50 × 3.10 0.48
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so that's
24A @ 15.2V, care to explain me (with your beloved Ohm's law
) how the TEC could draw more current at a lower voltage??? (not a very readable quote, i know). Ohm's law works wonder if you use it for resistor (even capacitor and inductance if you calculate their "R" value correctly), but do you
really think it can give you accurate value (of I vs V) for the junctions/couples found in a TEC?? It might be possible, but I doubt
you will be able to link Ohm's law with the Seebeck "effect".
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It's not exactly a hard calculation
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