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Unread 04-27-2004, 09:25 AM   #6
nicozeg
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Join Date: Sep 2002
Location: Santiago, Chile
Posts: 403
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Quote:
Originally Posted by bigben2k
Formulae:
Q=-k*A*dT/L

where:
Q=let's say 75 Watts
k=400W/m*°K, 150 for Silicon
A=0.0001m^2 (10 mm by 10 mm)
L=0.001m (~1 mm thickness)
dT=X

Silicon:
75=-150*0.0001*X/0.001
I can resolve X to: 5 deg C, which is the delta T.


So to get a delta T of 5 deg C with copper, the distance (L) must be:
Q=-k*A*dT/L

Q=let's say 75 Watts
k=400W/m*°K
A=0.0001m^2 (10 mm by 10 mm)
L=X
dT=5

75=400*0.0001*5/X
I can resolve X to: 2.7e-3 (0.0027)

And that's 2.7 mm.
There's a lot easier formula:

400/150 = 2.666

It's useful to discard redundant and irrelevant data before making the calculations (and more precise too)
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