Quote:
|
Originally Posted by Jabo
No, I have family to provide for and time spent doing this extensive calculations would mean no money for my family, as simple as that.
It so easy to criticise isn't it BillA?
At least I am not judging anyone here what you seem to enjoy to the extremes.
Do not pass judgement where you have no reason nor right to do so, especially if it considers somebody personally, not ones 'theories'.
|
What kind of calculations do you plan on doing with no data or numbers of any sort to work with? All you need to do it provide some sound theory or basis for your claims.
Consider this: an electrical circuit with a battery supplying voltage V, and two resistors of values X and Y ohms. If you wire up the resistors to the battery in series, the circuit as a whole will have resistance (X+Y) Ohms (assuming the wires have negligible resistance). So by Ohm's Law, current through the circuit is I=V/R which is the same as V/(X+Y). If you then switch the order of the resistors in the loop, you could say that total resistance is now (Y+X), and we know that's the same as (X+Y). Now, despite changing the order of devices in the loop, the resistance is still the same and the current is still I=V/(X+Y).
Now I realize that there are some differences (non-linearity in flow-pressure relations, but at constant flowrate it shouldn't even matter), but does the same principle not apply to a watercooling loop? Battery voltage V is equivalent to pump pressure, current is equivalent to volumetric flowrate, resistance R is equivalent to flow resistance. Each resistor has a set voltage drop in the circuit just like each watercooling device has a set pressure drop, regardless of its position in the loop.