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Originally Posted by Groth
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Given 32 mm square copper heatspreader 1 mm thick, heat it with a 10 mm square 100 watt uniform heat source, cool the opposite side with a heatsink with an h(eff) of 20,000 W/m^2, what's the heat flux density at the heatspreader/heatsink interface?
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My interpretation of Waterloo suggests that the spreading would result in a reduction of the c/w , even with a layer of TIM between IHS and HS.
TIM layer is simulated as 0.1x32x32mm of 10w/m*c material.
Might prefer a circular Die simulation.
For this Waterloo, additionally, calculates for Parabolic Flux distribution.
Edited and corrected.
Edit2 : Corrected "Kryotherm" to "Waterloo"