Some of your assumptions smell wrong to me, Heatwave.
First of all, a 30C difference in water temp is not feasible for this application. More than 6kW would melt the PC.
Next, you assume 45C water will match the CPU temp, but this completely ignores the waterblock's function. Remember that the block will have a C/W of (very roughly) .1, so CPU temp will always be significantly higher than water temp. With your 6270W example, the CPU would be more than 600C hotter than the water. This might hurt your overclock a bit...
Your radiator calculations have similar problems, I think. Is U=25 a reasonable number for passive operation? Air's specific heat is about 1/4 water's. Thus cooling 3lpm of water 30C with a 10C increase in air temp would require 36kg of air per minute. That works out to about 1000cfm (sorry for the units, but cfm is something we all know). Will you get 1000cfm without fans, even with a 14m^2 radiator?
I suggest you put that 350W goal into your equations and try again.
(edited for typo)
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Last edited by HammerSandwich; 07-06-2004 at 04:10 PM.
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