Heat removed isn't linear, it'll be roughly Q=2*Qmax*I%-Qmax*(I%)^2. So at 79% of Imax of the original 226W pelt, you'll get 2*226*.79-226*(.79)^2=216 watts of cooling.
If you make a graph of that, you can see why it's best to choose a large pelt and undervolt.
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