Quote:
|
Originally Posted by Razor6
If the core has 15 tubes then the answer should be about 2.5 sq ft.
Code:
15 * 2 * 6 * 2
------------------ = 2.5
144
Your rad should perform much better than mogwai's, 16sq/ft is huge.  |
My math was...
Each fin is 2x6, since its 2 sided that 24 sq in a pice, the heatercores I have each have 68 fins. so 68 x 24 / 144 is about 11.33.
A gerwin rad and a normal heatercore are apples and oranges. In a normal heatercore heat must travel through both solder and thin fins to get to the air. In a gerwin rad it must only travle through the wall or the pipe. However a downside to the gerwin rad is the water may flow to evenly and the center not cool off as much as the slower moving exterior.