Overall I agree with your rationale
However have difficulty with thumbnail 1(now graph 1,again)
Dealing only with parallel bp
For given bp area, say 50x50mm, h(eff)=50kw/m^2*c(=h(conv) no surface structure) and varying thickness.
Would split the resistance into components :
Used
Waterloo for calcs
Did not include zero thickness (logic probs)
Dunno how to calculate for hemispherical bp.
Intuitively think will be improvement
Thumbnail 2(graph2) is similar to my original flat bp guesses(presented
here,for example)
Dunno how much using hemisphere would alter the situation