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Originally Posted by MaxxxRacer
if u think so.. prove it....
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No you're completely wrong. Pressure drops are cumulative, and depend only on the componets and flow rate.
Since the flow rate is constant in a series loop, and the construction of a block is fixed, the pressure drop doesn't depend on order.
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think of it this way.. is there more pressure when there is 10 feet of tubing or 1 feet of tubing. 1 foot of tubing of course.. that means that the closer the head is to the pump the more pressure it gets. its quite simple. By the time the water gets to my res (my system is pump cpu gpu rad res) there is less pressure (force) than if it is in the cpu which is only 9 inches of tubing from the impeller of the pump.
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You're confuseing pressure drop with pressure generated.
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Another way to think aobut it. what happens after the water goes through the cpu block. In my case the tdx. It slows down like a mother F. thats becasue of the backpressure that is caused in the tdx. well the RAD will do the same thing. just not as bad as its not as restrictive as my tdx with the insert im using.
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No it doesn't slow down. Flowrate entering and exiting a componet is equal, or the part is leaking.
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I hope that clears things up Althornin.
And dont try to pull the "closed loop" stuff on me. I know that things arnt exactly the same in a close loop, but physics doenst get thrown out the window in a closed loop. One way to test htat is to put ur cpu block before the pump and have the pump suckwater from a big jug of water. and then do the same test with teh cpu block after the pump. with the cpu block after the pump you will see higher flow rates.
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Ugh if you're going to be pretentious and incorrect, at least use proper grammer when you do it.