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Output · 12-03-2004, 07:46 AM

Cathars post does not mention that the rest of the heat from the pump is added to the air in the case. for me, as I have 2 rads and a psu as the only way out for air, this will most likly pass my rads(since way more air is passed there than from the psu), therefor "readding" the heat to my loop.
I would see that your point is correct if the pump is outside of the case, or that you have extra fans removing heat from the pump.

Since at least my pump is not near a "output" fan, all the air inside the case will be heated, thus heating all system components by about 12w(ehiem 1250)

12-03-2004, 07:46 AM	#3
Output Cooling Neophyte Join Date: Oct 2001 Location: Sweden Posts: 31	Cathars post does not mention that the rest of the heat from the pump is added to the air in the case. for me, as I have 2 rads and a psu as the only way out for air, this will most likly pass my rads(since way more air is passed there than from the psu), therefor "readding" the heat to my loop. I would see that your point is correct if the pump is outside of the case, or that you have extra fans removing heat from the pump. Since at least my pump is not near a "output" fan, all the air inside the case will be heated, thus heating all system components by about 12w(ehiem 1250) __________________ parallel rads is the only way to go!