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Originally Posted by pauldenton
iirc = if i remember correctly.....
at (say) 4 litres/minute (just over 1 US gallon/minute and a low flow rate for a system) once a steady state is reached (i.e. the water temperature has risen to the point at which the rad(s) shed heat as fast as the pump+blocks add it) a 70 watt CPU would only raise the water temp by approx 0.25C i.e the temp after the block would be a quarter of a degree higher than that before it.
{specific heat capacity of water is 4.186 joule/gram °C, 4 litres of water weighs 4kg so 66.667grammes per second flow through the block. therefore since a watt = 1 joule/second it would need about 279 watts to raise the water by 1C}
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Ok I'm new to water cooling but let me see if I understand what your saying. Once the temperature has reached the "steady" point that in this case it would take an extra 279 watts to increase 1C. I could see this working in a setup with just one heat source and one rad. However, the affect of multible heat sources in series changes this calculation as the heat is increasing at each source with only one rad to cool. The water coming off the CPU is warmer than what is going in correct? If not why does it matter which direction you run the water through the block? That warmed water is then going into the GPU block. Each stage heat is added will have greater affect. If your theory applied then it also would not matter what order you ran the water Pump, CPG , GPU, RAD, Pump or Pump, GPU, CPU, RAD, Pump. You could even run Pump, RAD, GPU, CPU, PUMP. Yet the first setup is the one most people seem to use because it gives the coolest CPU temps. Atleast this is what I have seen and what others have reported online.