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Unread 12-20-2004, 09:46 AM   #29
mtbdrew
Cooling Neophyte
 
Join Date: Nov 2004
Location: Keller, TX
Posts: 10
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Quote:
Originally Posted by pauldenton
the actual amount of liquid in the system will only affect the time it takes to reach equilibrium, not the equilibrium temp. the heat sources add heat at (virtually) the same rate irrespective of water temperature - but the rad(s) ability to shed heat is proportional to the temperature differential between the water and the air
http://thermal-management-testing.com/ThermoChill.htm

so the water temperature will rise until it reaches the point at which the rad sheds heat as fast as the pump/blocks add it.... the more liquid in the system the longer it will take, but we're talking minutes unless you have an enormous res.

once it reaches equilibrium it doesn't matter whether 1 litre circulates 4 times a minute or 4 litres once a minute - a smaller volume heated and cooled more often is just as good at moving heat from one place to another.
Thanks for the mental work out, you are making me dust the out corners I have not used in a while.

One point you are still missing though. You are making the assuption of the heat being applied at one time. However, it is being applied by five different sources which cause a 5:1 ration of heating to cooling. This of course is a simplified way to look at it. To do this accurately you would have to measure the time it take for a set amount of water to travel through the rad and each heat source. But for this example lets just say it takes 1 second for a millileter of water to travel through each device. In this case for every second of cooling you get 5 seconds of heating. The calculation is made moore complicated because each heat source is a different value but you get the general idea. To go back to my original state he will either need a monster rad or two seperate rads. Either methods should increase the amount of time the water gets cooled. Ideally you would want a 1:1 ratio to bring your calculation back into line.
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