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Presumably, with a 5'C delta T, it would dissipate 750 watts, or thereabouts? Also, is heat dissipation linear with airflow, so if I halve the airflow, I get 375 watts?
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If you double the airflow, your temp will drop, but the dissipation will still be the same. So it doesn't really make sense to think about it like that. But yes, if you regulate temperature exactly, and can exactly half airflow, you would expect roughly half the dissipation. Realistically though this is only going to apply for relatively small changes in airflow. THere is only so much and so little air you can crame through a rad before the gas dynamics are going to start to have an effect on things (speculation on my part, I've never tried to measure it).
More interesting would be to estimate a C/W curve for your radiator, plug in your dissipation, and try and guess the temp. Unfortunately radiator thickness, flow resistance, fins per inch, and material will all be different then a heatercore, so getting accurate numbers with out doing the measurements your self is nearly impossible.