By heat dissipation do they mean the energy that does not become pump heat?
Here's a likely flawed, but easier, way to get pump heat.
Get an insulated reservoir (jug in an ice chest had ought to do it - maybe use a styrofoam chest so you can easily poke holes for hoses).
Pump goes on the outside, but very close to minimize heat loss through hoses. A measured amount of water goes in the system, at room temp. Run system for an hour (or six - whatever seems appropriate - just run long enough for an "easy to measure" heat rise).
Water temp rise times water mass divided by time had ought to be your pump heat (just like a dyno). Energy input minus pump heat had ought to be dissipation (where else is it going to go?).
You'd need some sort of resistance in the line to get the pump doing a "typical" amount of work.
Speaking of resistance, a long time ago I was at the Moto Guzzi factory. They had the dyno there plumbed to fountains in the courtyard so you could always tell when they were engine testing. Of course, they couldn't have been using measured temp rise. I think they'd already calculated the energy required to push the water jets to different heights. I asked, but my Italian wasn't (and sadly still isn't) good. Beautiful place for a ...hmmm... "factory" isn't exactly the right word - "large series of workshops" is maybe more like it - Guzzis were hand-built the same as Vincents once were - only with post WWII equipment
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