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Originally Posted by Exie
Can I ask a silly question, what does "0.1C/W" refer to ? heat absorbed by copper heatsink from the Pelt ? Some sort of themal efficiency ? <shrug>
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It the ratio of temperature difference per watt of heat moving through the heatsink. So, if you have 0.1C/W and you have 40W, 80W or 100W, you would have a hot side that is 4C, 8C or 10C hotter than the cold side. The cold side is the one exposed to air, water or other coolant. The C/W figure is constant for any ambient temperature and heat being moving through the heatsink (within the normal range that we work with). Look at all the waterblock reviews we publish.
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Originally Posted by Exie
I accpet that 80W pelts may not cool my water block & coolant by much, but I'd be happy with modest gains. Coolant temp currently sits at about 35c, if I could knock 5 or 10 degrees C off it, I'd be happy.
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I'm guessing that you'll be lucky to knock 1-2C off your coolant temp. But, I'd love to be proved wrong.
Why? Secondary thermal paths, and the fact that your peltiers won't actually be moving 160W of heat since the temperature differential won't be zero. Peltiers get a LOT more efficient when you make their heatsink better.