Ok.
So if more surface i the key then i should save the drill cones.
If i remove them the area is going to be 2*2=4mm2
If i leave them i vill have a cone surface of M=pi*r*1,28=4.02mm2
Then i vill have to ad the remaning flat area of A=(2*2)-(1*1*pi)=0,85mm2
So area without a con is 4mm2
And a area with a cone is 4.87mm2
So my Core 2 quad is W40mm*D40mm so to make it symetrical i have to ad 1 row of pins, thats 40*42mm = 11row with 10 pins each.
Then i vill have to drill 310 holes
That makes the surface on the block 1509,7mm2=310*4,87
A increase of 269,7mm2 compared if it would be plainflat. (a bit bigger then your thumbnail)
And wen it coms to if its a high or low flow block.
The pins is going to be standing like this.
http://img187.imageshack.us/img187/1033/namnlsku8.png
So the water is forcet to go around evry pin (yes im going to make a beter blueprint in autocad, paint dosint cut it
)
I will use 1/2 (12mm) tubing thats 113mm2 through put
And i vill have 2*6*10=120mm2 in the block.
The pump is going to be a danger den 12V D5 or equal.
So my guess is that i vil have a thicknes of 4mm, but let the cons go down 0,8 mm extra.
so 3,2mm to the cone top and 4mm to the normal surface.
Dos it sound good?