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More time in rad means that the time the water has to cool off is longer... Just realized that it's kinda hard to explain
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i dunno how to explain this but the total time the water stays in the radiator is the same no MATTER what rate the water is flowing. Think of it this way, if a water molecule takes ten seconds to circle a complete cooling loop and during each loop, it stays in the radiator for two seconds, it would then be in the radiator for 12 seconds per minute.
60 secs / 10 secs/loop = 6 loops per minute.
6 loops/minute * 2 secs (in radiator) / loop = 12 seconds in radiator per minute.
Let's speed up the flow to complete a cooling loop every five seconds, and that same water molecule only spends 1 second in the radiator per each loop. If you calculate the total time it stays in the radiator, guess what? It's still 12 seconds!
60 secs / 5 secs/loop = 12 loops per minute.
12 loops/minute * 1 sec (in radiator) / loop = 12 seconds in radiator per minute.
This formula also applies to residual time of H2O in the waterblock in terms of heat transferred to the coolant. Even if the flow is as little as .10 gpm, the residual time within the radiator would still be the same. So, as you can see, residual time of a liquid coolant within the radiator (or any other heat exchanger) is a constant as long as there is some sort of continuous flow of the coolant in a looped system.