hmm.. for a given i.d. u'd be able to get a fixed amount of volume V in a period of time T in a single tube... if u Y that tube into 2 tubes that are the same size as the original tube u'd have to push 2x the volume of water in the same amount of time in order to retain the fixed volume per time that u originally had. So in order to get V/T in each of the new tubes u'd have to have 2V/T in the feed tube to the Y provided it's laminar flow and the Y divides them equally and there is the same restriction at the end of each.
Right?
Cyph3r
please pardon the variables
just got done with algorithms homework