Quote:
Originally posted by bigben2k
Besides, if we didn't do that, we wouldn't have noticed that this simple test also involves taking the result of the weight of that water column, convert it to psi, and multiplying it by two, since the rig is still running, and the pump will split its load between the cooling loop and keeping that column up.
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Actually, the pump won't expend any energy keeping that column up that it isn't already expending. It "keeps that column up" simply because of the resistance provided by the cooling loop.
PS: 1 psi = 27.708 in H2O = 2.036 in Hg = 6894.8 Pa