Quote:
Originally posted by myv65
The tubing portion is pretty easy to explain. It acts very much like a spring in a mechanical system. It will stretch (dilate) when a pressure gets applied. This stretch is very minor, but represents some finite change in system volume. The storage energy is simply delta-P (running versus stopped) times the system volume. It's not so easy to calculate, but is completely immaterial. Once you reach steady-state, stored energy has no bearing on the matter.
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You're absolutely correct.
So that leaves what I was saying, which is that the energy (efficient part) supplied by the pump, fights friction, which turns into heat.
I'm at the end of the tunnel now... I think!
Let me try to apply this info:
Let's say that I set up a rig. It doesn't matter what it is, as long as it's the same.
In rig A, I use a 1000 gph pump, and I achieve a 200 gph effective flow rate. In rig B, I use a 400 gph pump, and achieve a 100gph flow rate. (pump sized accounting roughly for the increased restriction at the higher flow rate)
I get a higher flow rate in rig A than in rig B, but I'll have induced twice as much energy in the water.
Does that look about right?