Yeah, I butchered that. What I meant is that in every point in a closed loop system you're going to have a certain amount of water pass a point per second. If one section of the loop is wider than the rest, the water doesn't have to flow as fast to move the water at the same rate through it. It is kind of like how at a narrow point of a river it'll run fast and how at a very wide point it'll run very slow. When running two channels of equal area as opposed to one channel of the same area (cross section area is what I'm getting at) as one of the two channels by itself, your water will, in effect be running at half of the speed as if it was running in that single channel. The FLOW RATE will be the same, as in the same amount of water passing through that area in the same amount of time, but overall, the water will be slowed down because the breadth of its path was widened. I don't think that made any more sense, did it? It's easy to visualize, but I'm having a bastid of a time describing it.
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#!/bin/sh {who;} {last;} {pause;} {grep;} {touch;} {unzip;} mount /dev/girl -t {wet;} {fsck;} {fsck;} {fsck;} {fsck;} echo yes yes yes {yes;} umount {/dev/girl;zip;} rm -rf {wet.spot;} {sleep;} finger: permission denied
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