Take the 0.5" ID data:
total head loss = loss from tube's length + loss from tube's bend
so ht = hb + hL
ht = Kbv2/g + f(L/D)v2/g
Kb = 42f (tabulated in Crane r/d = 8/0.5 or 16)
L/D = 18/0.5 or 36
ht = 42(v2/g) + f(36)(v2/g)
ht and v are known as is g. Just a matter of plug into spreadsheet and get units right at that point, right?
|