I lost it...
I have this formulae from a nice fellow from TechRep, but I lost how he came up with the numbers.
Maybe some guru can look at this, and point out what I'm missing?
The formulae is S= (Qm x Gl) / (N x D^2 x Fa x Fm x Fc x Fp x Gf^.5 x Hm^.5)
S: I don't know, I forgot!
Qm: flow (in gph)
Gl: base specific gravity
N: conversion constant
D: line ID
Fa: temp corr
Fm: manual correction
Fc: Rd corr
Fp: flow comp ratio
Gf: flow specific gravity
Hm: differential pressure (in inches wc)
The data I originally gave him was:
flow rate: 250 gph
line ID: 3/4 in.
outlet: 3/16 in. or 1/8 ?
fluid: water
Here are the values he used to determine the pressure drop (from the worksheet he faxed me):
S = 0.03957
Qm: 250
Gl: 1.0
N: 340
D: .75
Fa: 1.0
Fm: n/a
Fc: 0.99
Fp: 1.0
Gf: 1.0
Hm: ?
Fc comes from a graph. Hm was calculated to be 1113" wc, but I think it was meant to show the inlet pressure, because he calculates an 80% pressure drop to come up with an outlet P of 890" wc.
but what is "S", and how did he come up with it?
Anyone? Help!
