Quote:
Originally posted by Graystar
Pumping water around and around will NOT cool the water faster. Why? Because of every loop you have a waterblock adding 6 therms of energy to the water!
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If you reread my post, though it is possible I didn't make the point clear enough, there is no waterblock in the situation I have described.
I was merely describing two situations where we are attempting to cool the same 10 litres of water from the same temperature with the same radiator and no additional heat load. The only difference is that in one scenario, we have water moving, breaking down the barrier layer, and in the other, we have the water stationary with effectively a full barrier layer, ie the thermal energy from the water at the center of the tube/channel must conduct through the water rather than turbulent flow randomly carrying it into the copper wall.
And yes, I agree that the water entering the rad will be cooler, but each "packet" of water is carrying less thermal energy.
It is plain to see that the radiator will dissipate more heat if the water is warmer, but it doesn't have to dissipate more heat. The heat load is set by the processor.
We know that the processor will rise to such a temperature that the thermal gradient across the WB baseplate transfers 70W of heat. However, this does not determine the water temperature directly. The water temperature will be set by the efficiency of the radiator and the resulting delta T required over the ambient air temp so that it can remove the 70W.
If you suddenly slow the flow rate down in a watercooling loop, it is the reduction in the efficiency of the radiator which will cause the overall "average" water temperature to rise. This in turn will cause the cpu to heat up to a temperature where the delta T is sufficient to transfer 70W to the water.
I'm not separating components as such, merely working back from the only fixed variable we have, the air temp, at each stage considering the efficiency of the heat exchanger and the corresponding delta T required to move 70W, which is all we are asking the system to do.
Ask yourself, this, how is it that increasing the efficiency of both the waterblock and the radiator would result in an increase in the cpu temp, as this seems to be what you're implying.
8-ball