Quote:
Originally posted by 8-Ball
Oh go on then, one more try.
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At my job we have an internal chat system. Sometimes one person is trying to explain something to another, and for some reason or another, the knowledge is just not getting through. So one person calls the other on the phone and 30 seconds later they realize they were saying the same thing and that everyone's understanding is in the right place.
Such is the difficulty of trying to explain things in text in a fluid discussion. What I type may make sense to me (at the time) but not to others. So, maybe if we keep this up we might all end up on the same page at some point.
Your description of the temperature changes is correct, but that's not what I was addressing.
What I was saying is that you can't keep the core hot for free.
The CPU is at a temperature above ambient and remains there so as long as the computer is on. Some thermal energy is used in maintaining that elevated temperature. So when a processor dissipates 70W of power in one hour, I'm saying that 238 BTUs are removed by water cooling, and 1 BTU is used keeping the core hot. (values are demonstrative only)
So, when you increase flow, and increase the heat transfer rate of the system, you will now remove 238.1 BTUs during that hour, leaving .9 BTUs to heat the core. This give us a cooler core.
So you really are removing more heat, but the amount of thermal energy produced and transferred remains the same (as it must.)
I hope that's a better explanation.