i think its sinking in, or something is
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varying flow in a pc-w/c single closed loop does not change time in the exchangers, quote cathars example
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The best way to think of it is like this.
In a fully bled system, name any time in which there is no water in the waterblock?
ie. there is no such time.
Therefore there is water in the block all the time. Regardless of the flow rate, the water spends the same amount of time in the block.
If we want to talk about packetised concepts, think of a car running around a circular race track. For an example, let's assume that the waterblock is a 60m (meter) stretch of road, and the racetrack is 600m long.
How many times per hour is the car inside the 60m section, and for how long?
If the car travels at 10m/s, it's in that 60 meter stretch for 6 second. In an hour the car travels 36000m. The racetrack being 600m long, means that the car go around the track 60 times in an hour. The amount of time spent in the 60m waterblock section is 6 seconds x 60 = 360 seconds.
If the car travels at 20m/s, it's in the 60m stretch for 3 seconds per lap. In an hour it travels 72000m, and will have completed 120laps in that time. 120 x 3 = 360 seconds.
The car has spent exactly the same amount of time in the "waterblock" stretch, regardless of its speed.
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that said increased flow in same system does offer perfromance benefits in terms of decreased boundary layer, increased turbulence etc.
The power plant scenario though i 1st viewed as single closed loop, is far from it due to numerous cascaded loops & changes of states etc, so its the 'single shot' through the exchanger i think that explains it to me. That right? .... in laymans terms