[neoacid]

Thanks for the feedback. I think i didn't explain my concept too well, but that's okay. I also realize that my concept is far from the optimal solution, but I hope it would be somewhat functional.
V12|V12, I'm interested to know what you think about what i am about to say, so please post back.

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Originally posted by V12|V12:

#1 That incline angle is going to FORCE the incoming water+air (Lets call it "mulch") down into to the water. Now since the mulch is moving rapidly, it has to pass through air, which would lead one to think that the air in the H20 would be released... Nope, it's moving too fast. So now it passes through another barrier of resistence, the H20; which the red indicates a swirling that will happen b/c the surface of the still water is being penetrated by fast moving air/water, which will actually push down MORE air into the water.
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Like i said, i know my design isn't optimal, but I do believe the slide would reduce velocity of the water falling in the reservoir due to friction (yes, small though it may be and even though the angle is fairly steep). Also, due to the fact that the water will spread out along the surface of the slide, this should help to keep as much air from being mixed in where the falling water interfaces with the pool of water. There will still be swirling, but this should be a lot better than just letting the water free fall from the top of the reservoir and take a direct path (water current) to the outlet at the bottom.

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Originally posted by V12|V12:

#2 Now that the mulch has made it down further into the water, and has release some air, while pulling some down with it, now that incline (I assume it will be the same width of the tube diameter?) creates a flow bottle neck for the outlet going to X-location. When the mulch travels down the incline and past the "lip" of it, some of the water will again be moving very fast and some slower, which will create another looping, which again, will mulch up the remaining air that's along with it.
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Well, yes it might look that way, especially because my drawing was very poor. I already had in mind that side of the wall and the lip of the slide should not be too close together or this would create resistance. As long as the total surface area between the side of the wall and the lip is adequate, this will be no more flow restrictive than your tubing. Ideally, we want to slow down the water to release the air, so the more space the better, even though i don't consider the water to be moving slow enough at this point to really do any good. It is after the water gets past the slide that the water should slow down even more because it will be entering a larger pool of water. This larger pool of water should be less turbulent and more bubbles should be released here. This is also why I consider this part to be the air-trap side of the device. The first part down the slide acts more like the reservoir.

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Originally posted by V12|V12:

#3 Ah, the slower moving water+air will now be released on the other side of the incline? Argh... Since the incline is blocking half of the res, the suction side (outlet at buttom) will be pulling as much water down as possible, limited by the incline's distance from the tubing wall. So you will have a Suctioned side. Meaning that there is more restriction of flow on that side, so ANY water that comes past the incline will be sucked down FAST, now the air really has NO chance of escaping to the non inclined side.
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I dont think this will happen anymore than in any other device. Of course the water will be moving faster the closer it is to the outlet. That will be true for every device, but not all of the water will take a direct path to the outlet. Some of the water will go directly to the outlet, and some of it will be allowed to flow to the rest of the reservoir. I also think the suctioning can be minimized by how far the slide's lip is from the bottom of the reservoir. (see picture)

For #4, a shallower incline angle will necessarily make the reservoir have to be larger (not desirable) to keep #1 from happening.