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Unread 11-23-2003, 05:20 AM   #7
Dieter@be
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Join Date: Nov 2003
Location: Belgium\Wetteren
Posts: 94
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So that makes:
Heat transfer/time = k*A*tempdifference/copperthickness

with k the thermal conductivity of copper.

That means, to increase the performance of the block:
1)make the copper barrier between water and core as small as possible.
2)increase surface area.

Pretty logic aint it. Although you'll see in my drawings that there is a little "hill" on the bottom piece, above the core, which is not according to 1), but i believe this way the water can get away much better.
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