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Water Block Design / Construction Building your own block? Need info on designing one? Heres where to do it |
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#1 |
Cooling Savant
Join Date: Sep 2002
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How deep would two 1/8" channels have to be in order to equal a 0.375" inlet??
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#2 | |
Cooling Savant
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#3 |
Cooling Savant
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thanks
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#4 |
Cooling Savant
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can you tell me how you deterrmined that for future reference??
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#5 |
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For a 0.375 opening, the radius is 0.1875.
Following the formula: pi*r^2, the area of such an opening is 0.11 in sq. two 1/8 channels is 1/4 by X, where X=.11/.25, which equals 0.442 . |
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#6 | |
Cooling Savant
Join Date: Jul 2002
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area of inlet = pi * r^2 = 3.1416 * (.1875^2) It's all algebra from here: x = (pi * (.1875^2))/(2 * .125) = .11045/.25 = .4418 Hope that helps Bob
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#7 | |
Cooling Savant
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#8 |
Cooling Savant
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All that's well and good, but don't forget that often times a fitting "size" does not match the true opening size. eg, NPT pipe sizes are "nominal" and never is the inside diameter of NPT equal to the "size". As another example, tubing fittings often have IDs much smaller than the "size". A 3/8" tube to NPT has an ID of only 0.22" on the hose barb end.
Always be certain you know the true diameter of the fittings in use in your system. |
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#9 |
Cooling Savant
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Thanks
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#10 | |
Thermophile
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