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Xtreme Cooling LN2, Dry Ice, Peltiers, etc... All the usual suspects

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Unread 08-06-2002, 08:21 PM   #1
Anomaly2181
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Default any pelt/tec's above 220 watts?

Just wondering if anyone has found any peltiers above 220/226 watts that are under 50mm*50mm. Trying to decide on what pelts to use since I have an uber 40 amp power supply.
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Unread 08-09-2002, 07:07 PM   #2
Wayne Harrow
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Yep i think there 48x48 or 50x50 but there no bigger dangerden.com have a 226w tec and extremecooling.co.uk sell a 220w tec.
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Unread 10-14-2002, 11:32 PM   #3
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swiftech has that 400w tec combo but i'm sure ur not interested in that. its composed of 2 tec's and comes with 2 waterblocks quite impressive
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Unread 10-15-2002, 12:18 PM   #4
Anomaly2181
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yah that swiftec sounds cool, I'm more interested in going part to part rather than a set though. Since my power supply is running at 13.2 volts I would be getting a tec that runs at the specified wattage at 13 volts. The 220's and 226's I think run off of 24 volts so they would run at half power if I had them hooked up at 13. P(wattage)=I(curent in amps)V(volts)
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Unread 10-17-2002, 09:58 AM   #5
Wayne Harrow
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No the 220 and 226w tecs run at 15.1v
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Unread 10-17-2002, 07:36 PM   #6
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Ok given that they are 15.1 volts then the number of amps they are going to pull maximum taking the 220 watt tec: 220watt/15.1 volts = 14.56amps. Ok well thats all fine and dandy most people think since I have a 40 amp psu, but in actuality whats going to happen: take the calculated tec amperage of 14.56 and pop it back into the power equation: P=IV...... P=(14.56 amps)*(my 13.2 volt supply)....P= 192.19 watts. So that would be the maximum value the 220 watt tec is actaully able to do. If there is a such thing as a 12 or 13 volt tec with plus 200 watt rating that would be cool.

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Unread 10-18-2002, 05:39 AM   #7
Wayne Harrow
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Na it dont work out like that they draw around 22-24 amps at 15.1v and put out around 360w of heat.
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Unread 10-18-2002, 12:29 PM   #8
Anomaly2181
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ok so they operate at 332watts 15.1*22? I thought it was like they put out 220 watts of heat, but because they are an ineffient device, they might only cool at 75% so 165 watts of cooling.
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Unread 10-18-2002, 01:13 PM   #9
Wayne Harrow
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Yea i see where your comming from.
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Unread 12-20-2002, 12:17 AM   #10
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I think someone needs to clear this up to avoid further confusion. This thread has given some people ideas that do not follow the laws of thermodynamics so I will try to clear them up the best I can.

I will use these figures for the Potted HP-199-1.4-0.8 from TeDistributing

If a device is rated at 24.6 volts and running at 11.3 amps the device requires 277.98 watts of power to get it running at full power. But on the website it lists its deltaQ(entropy) as 172 watts. Doing the equation 172/277.98 gives us the actual efficency of the device not the iMA so to speak. This means that it is 61% effective. This 61% does not mean to only send 172watts of power to it by using a powersupply that is a lower voltage. you could figure this out by 172watts=V*I. If 277watts is sent into the system and only 172 of work is done by the power... Lesser gains would be found if you sent 172 watts into the system. Using the 61% constant for this device(if you do not believe me that the Volts and amps are constant look at the second graph of any device on tedist and prove me wrong) That means that only 104.92 watts would do work.

If any of this is wrong please reply and explain your reasonings on it.
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Unread 12-20-2002, 02:14 AM   #11
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Acidwrz:

The rating for a peltier is how much heat (in watts) they can transfer at zero degrees delta T, it has nothing to do with how much power they use.

Go take a look at those graphs again. The 61% is constant for 0deg delta T or 0 watts heat transfer. As per the charts you referenced.

Take a look here:Typical Device Performance

If you really want to know how a peltier will perform download melcor's Aztecā„¢ software.

Using the chart referenced (172W peltier): if you transfer 68W of heat you will have a delta T of about 37 deg C with the hot side @ 25 deg C, it will draw about 9.5 A at 19.2 V = 182.4 Watts.
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Unread 12-20-2002, 12:33 PM   #12
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Yes i fully agree and understand what you are saying, but why would one not want to run at 11.6a 24.6v and achieve 40*C?
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Unread 12-21-2002, 10:28 PM   #13
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Quote:
Originally posted by Acidwrz
Yes i fully agree and understand what you are saying, but why would one not want to run at 11.6a 24.6v and achieve 40*C?
The reason you would not want to run at 24.6V as opposed to say 18.5V, (75% of Vmax) is that the power consumption of the pelt at 24.6V is 285 Watts. The power consumption at 18.5V would be about 163 Watts.

This additional heat has to be dissipated by the hot side watercooling. The more heat the hotside cooling has to remove the hotter the hotside will get. If the increase in hotside temperature due to the extra power dissipation in the pelt, exceeds the increased deltaT gained by running at higher power, temperatures will actually be worse when running the pelt at Vmax.

Some numbers from the Kryotherm simulator: (80 Watt Heatload, Rh=0.18C/W, Rc=0.1C/W, Rins=1, Ambient=20C)

Pelt Voltage = 24.6V
Hotside Temp = 84.3C
Coldside Temp = 21.8C
deltaT Hot to Cold = 62.5C

Pelt Voltage = 18.5V
Hotside Temp = 62.9C
Coldside Temp = 17.6C
deltaT Hot to Cold = 45.3C

You can see that even though the deltaT for the 24.6V case is higher, the Coldside temperature is lower when the pelt is powered with 18.5V. The optimal voltage to run at will depend on the quality of the hotside cooling.
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